Does listening to classical music during a mathematics test improve students’ test performance?

This OPTIONAL assignment can be completed to raise your Discussion Board grade. It is somewhat similar to the “intro definitions” post in that you must find an article in which the authors conducted a hypothesis test as part of the research reported on in the article. Usually, authors just give a few details of the test conducted. I want you to fill in the details. You should formally state the Ho and Ha, compute a test statistic and/or a p-value, showing the formula and some intermediate steps. And finally you should write out the conclusion as I have mandated for all hypothesis tests with both a statement about Ho and Ha and a statement that is context-specific. I have provided a sample post. This can boost your discussion board grade, but again is not required.


This is the sample post:
sample post
COLLAPSE
http://music.arts.usf.edu/rpme/effects.htm

Does listening to classical music during a mathematics test improve students’ test performance?
I had heard rumors that studies had found this to be true- that listening to classical music at a low volume level somehow caused students to do better on math tests. Looking at this article made me doubt that. I refer specifically to what is shown in Table 5. The mean test score for a sample of 64 students with no music was 12.0152 with a standard deviation of 2.754 and the mean of 64 students while listening to classical music was 11.8485 with a standard deviation of 2.707. So actually the “no music” or control group scored higher. It would not make sense to test whether listening to music significantly improves performance (although that is what the authors of the study actually did. I will look at, more realistically given what was determined) whether listening to music is DETRIMENTAL to math test performance.
Hypothesis test:
Ho: µControl ≤ µMusic or µControl – µMusic ≤ 0
HA: µControl > µMusic or µControl – µMusic > 0
Tcrit = 1.998 ( α = 0.025 in one tail and df = n – 1 = 64 – 1 =63 using the smaller of the sample sizes)
(Computed in Excel using =tinv(0.025,65) )

p-value = p(t > 0.345) = 0.365 > α
Conclusion: Fail to reject Ho. The small difference between the mean test score of students not listening to music and the mean test score of the students who were listening to music is not sufficient evidence to prove that the music was detrimental to the students’ performance.

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